(2x+1)/(x^2+4x+4)-6x/(x^2-4)+3/(x-2)

3 min read Jun 16, 2024
(2x+1)/(x^2+4x+4)-6x/(x^2-4)+3/(x-2)

Simplifying the Expression: (2x+1)/(x^2+4x+4)-6x/(x^2-4)+3/(x-2)

This article will guide you through the process of simplifying the given algebraic expression:

(2x+1)/(x^2+4x+4)-6x/(x^2-4)+3/(x-2)

Step 1: Factor the denominators

  • x² + 4x + 4 can be factored as (x+2)²
  • x² - 4 can be factored as (x+2)(x-2)

Now, the expression becomes:

(2x+1)/(x+2)² - 6x/(x+2)(x-2) + 3/(x-2)

Step 2: Find the Least Common Multiple (LCM)

The LCM of the denominators is (x+2)²(x-2)

Step 3: Adjust each fraction to have the LCM as its denominator

  • For the first term, we need to multiply the numerator and denominator by (x-2).
  • For the second term, we need to multiply the numerator and denominator by (x+2).
  • The third term needs to be multiplied by (x+2)².

This gives us:

[(2x+1)(x-2)]/(x+2)²(x-2) - [6x(x+2)]/(x+2)²(x-2) + [3(x+2)²]/(x+2)²(x-2)

Step 4: Combine the numerators

(2x² - 3x - 2 - 6x² - 12x + 3x² + 12x + 12)/(x+2)²(x-2)

Step 5: Simplify the numerator

(-x² - 3x + 10)/(x+2)²(x-2)

Step 6: Factor the numerator (if possible)

The numerator can be factored as (-1)(x-2)(x+5)

Step 7: Simplify the expression

The final simplified expression is:

(-1)(x-2)(x+5)/(x+2)²(x-2)

Final Answer:

-(x+5)/(x+2)²

Important Note: This expression is undefined when x = -2 and x = 2, as these values would make the denominator equal to zero.

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